Constructing a Subquery SQL Statement in Laravel 4.2

Data and Databases
1

I’m starting with Laravel 4.2 and need assistance in converting a complex SQL subquery into a Laravel-friendly format. I have a query that aggregates data based on conditional logic. Below is an adapted example:

SELECT id, COUNT(*) AS count_all FROM (
  SELECT record, 
         SUM(CASE WHEN status_ref.status = 'finished' THEN detail.value ELSE 0 END) AS finished_total,
         SUM(CASE WHEN status_ref.status = 'ongoing' THEN detail.value ELSE 0 END) AS ongoing_total
  FROM detail_records AS detail
  JOIN status_table AS status_ref ON status_ref.ref_id = detail.key_ref
  GROUP BY detail.record
) AS derived_table;

How can this subquery be implemented using Laravel 4.2?

2

hey jumpingbear, ive been tinkering with DB::raw to construct subqueries and it kinda works wonders. curious how layering the query builder with raw segments has worked for others. have u tried breaking the query into parts before merging?

3

Handling subqueries in Laravel 4.2 often requires a balance between using the query builder and DB::raw for parts of the query that become too complex to structure programmatically. My approach involved constructing individual segments of the query, validating their structure, and then carefully merging them. This helps in keeping the query understandable and eases debugging. Although the absence of more advanced Eloquent features in older versions necessitates some raw SQL, careful use of parameter binding and group by clauses can mitigate potential issues. This approach proved effective in my experience.

4

hey jumpingbear, try using nested closures to build your subquery. i used DB::table and few nested queries to perform conditional sums and groupBy. it keeps most logic builder-based while avoid too much raw sql chaos. give it a whirl.