I’m trying to figure out how to filter a Pandas DataFrame similar to SQL’s IN
and NOT IN
operations. Here’s what I want to do:
data = pd.DataFrame({'region': ['Europe', 'Asia', 'Africa', 'Americas']})
regions_of_interest = ['Asia', 'Americas']
# How can I do something like this?
data[data['region'] in regions_of_interest]
data[data['region'] not in regions_of_interest]
I’ve tried using merge, but it feels clunky:
data = pd.DataFrame({'region': ['Europe', 'Asia', 'Africa', 'Americas']})
filter_df = pd.DataFrame({'region': ['Asia', 'Americas'], 'keep': True})
# IN
result_in = data.merge(filter_df, how='inner', on='region')
# NOT IN
result_not_in = data.merge(filter_df, how='left', on='region')
result_not_in = result_not_in[result_not_in['keep'].isna()]
Is there a more straightforward way to do this in Pandas? I feel like I’m missing something obvious. Any help would be great!
hey luke, u can use isin() method for this. it’s pretty simple:
data[data[‘region’].isin(regions_of_interest)] # for IN
data[~data[‘region’].isin(regions_of_interest)] # for NOT IN
the ~ symbol is for negation. hope this helps!
hey there! have u considered using the loc accessor? it’s pretty neat:
data.loc[data[‘region’].isin(regions_of_interest)] # IN
data.loc[~data[‘region’].isin(regions_of_interest)] # NOT IN
it’s clear and concise. what do you think? any specific reasons you’re looking for alternatives?
I’ve encountered similar situations in my data analysis work. The isin() method is indeed efficient, but there’s another approach worth considering. You can leverage boolean indexing with a list comprehension:
data[data[‘region’].apply(lambda x: x in regions_of_interest)] # for IN
data[data[‘region’].apply(lambda x: x not in regions_of_interest)] # for NOT IN
This method offers flexibility, especially when dealing with more complex filtering conditions. It’s slightly more verbose but can be more intuitive for those coming from a programming background. Additionally, it allows for easy customization of the filtering logic if needed in the future.